Okamura I / Sueoka Y - Tang S / Zheng Z (1-2), resultado del partido, estadísticas y series
Eventos: Okamura I / Sueoka Y
ITF China F4, Men Doubles
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| Redondo 27 | |||
| 2024-06-20 | Okamura I / Sueoka Y - Tang S / Zheng Z | 1 - 2 | |
| Redondo 5 | |||
| 2024-06-19 | Okamura I / Sueoka Y - Wang Q / Zhang L | - | |
Estadísticas del partido
| 1 | Aces | 4 |
| 4 | Dobles faltas | 2 |
| 47/67 (70%) | Primer servicio | 49/69 (71%) |
| 16/20 (80%) | Segundo servicio | 18/20 (90%) |
| 32/47 (68%) | Puntos de primer servicio | 33/49 (67%) |
| 8/20 (40%) | Puntos de segundo servicio | 10/20 (50%) |
| 10 | Service games played | 10 |
| 7/9 (77%) | Break points saved | 4/6 (66%) |
| 66 | Total | 70 |
| 40 | Puntos de servicio ganados | 43 |
| 26 | Puntos ganados recibiendo | 27 |
| 7 | Máxima racha de puntos | 5 |
| 8 | Service games won | 8 |
| 16/49 (32%) | First serve return points | 15/47 (31%) |
| 10/20 (50%) | Second serve return points | 12/20 (60%) |
| 10 | Return games played | 10 |
| 2 | Break points converted | 2 |
| 0 | Tiebreaks | 0 |
| 10 | Total won | 10 |
| 3 | Max games in a row | 3 |
| 0 | Aces | 0 |
| 2 | Dobles faltas | 1 |
| 19/28 (68%) | Primer servicio | 19/30 (63%) |
| 7/9 (78%) | Segundo servicio | 10/11 (91%) |
| 13/19 (68%) | Puntos de primer servicio | 14/19 (74%) |
| 2/9 (22%) | Puntos de segundo servicio | 5/11 (45%) |
| 5 | Service games played | 5 |
| 3/5 (60%) | Break points saved | 0/1 (0%) |
| 15 | Puntos de servicio ganados | 19 |
| 11 | Puntos ganados recibiendo | 13 |
| 5 | Máxima racha de puntos | 4 |
| 5/19 (26%) | First serve return points | 6/19 (31%) |
| 6/11 (54%) | Second serve return points | 7/9 (77%) |
| 5 | Return games played | 5 |
| 1 | Break points converted | 2 |
| 0 | Tiebreaks | 0 |
| 1 | Max games in a row | 2 |
| 1 | Aces | 4 |
| 2 | Dobles faltas | 1 |
| 21/29 (72%) | Primer servicio | 22/29 (76%) |
| 6/8 (75%) | Segundo servicio | 6/7 (86%) |
| 16/21 (76%) | Puntos de primer servicio | 14/22 (64%) |
| 4/8 (50%) | Puntos de segundo servicio | 4/7 (57%) |
| 5 | Service games played | 5 |
| 4/4 (100%) | Break points saved | 4/5 (80%) |
| 20 | Puntos de servicio ganados | 18 |
| 11 | Puntos ganados recibiendo | 9 |
| 7 | Máxima racha de puntos | 5 |
| 8/22 (36%) | First serve return points | 5/21 (23%) |
| 3/7 (42%) | Second serve return points | 4/8 (50%) |
| 5 | Return games played | 5 |
| 1 | Break points converted | 0 |
| 0 | Tiebreaks | 0 |
| 3 | Max games in a row | 1 |
| 0 | Aces | 0 |
| 0 | Dobles faltas | 0 |
| 7/10 (70%) | Primer servicio | 8/10 (80%) |
| 3/3 (100%) | Segundo servicio | 2/2 (100%) |
| 3/7 (43%) | Puntos de primer servicio | 5/8 (63%) |
| 2/3 (67%) | Puntos de segundo servicio | 1/2 (50%) |
| 0 | Service games played | 0 |
| 0/0 (0%) | Break points saved | 0/0 (0%) |
| 5 | Puntos de servicio ganados | 6 |
| 4 | Puntos ganados recibiendo | 5 |
| 3 | Máxima racha de puntos | 3 |
| 3/8 (37%) | First serve return points | 4/7 (57%) |
| 1/2 (50%) | Second serve return points | 1/3 (33%) |
| 0 | Return games played | 0 |
| 0 | Break points converted | 0 |
| 0 | Tiebreaks | 0 |
Okamura I / Sueoka Y - Tang S / Zheng Z
ITF Masculino, ITF China F4, Men Doubles, partido Okamura I / Sueoka Y - Tang S / Zheng Z, hora de inicio 2024-06-20 07:20:00 la hora internacional.
Okamura I / Sueoka Y y Tang S / Zheng Z participa en el campeonato ITF China F4, Men Doubles, ITF Masculino.
El partido tendrá lugar en el estadio Court 8 en la ciudad Luzhou, China.
Eventos: Tang S / Zheng Z
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ITF China F12, Men Doubles
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| Redondo 27 | |||
| 2024-10-31 | Tang S / Zheng Z - MO Y / Zeng Y | 1 - 2 | |
| Redondo 5 | |||
| 2024-10-30 | Tang S / Zheng Z - Liu H / Zhang L | 2 - 0 | |
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ATP Challenger Hangzhou, China Men Doubles
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| Redondo 27 | |||
| 2024-10-10 | Rodriguez C / Romios M C - Tang S / Zheng Z | 2 - 1 | |
| Redondo 5 | |||
| 2024-10-09 | Bakshi A / Ursu V - Tang S / Zheng Z | 0 - 2 | |
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ITF China F13, Men Doubles
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| Redondo 28 | |||
| 2024-09-27 | Yang Z / Zeng Y - Tang S / Zheng Z | 2 - 1 | |
Ubicación
China
País
Luzhou
ciudad
Court 8
Estadio