Chan H / Kudermetova V - Danilina A / Xu Y (2-0), résultat du match, statistiques et séries
Événements: Chan H / Kudermetova V
WTA Finals, Doubles
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| Rond 28 | |||
| 2024-11-08 | Siniakova K / Townsend T - Chan H / Kudermetova V | 2 - 0 | |
| Rond 3 | |||
| 2024-11-07 | Errani S / Paolini J - Chan H / Kudermetova V | 1 - 2 | |
| Rond 2 | |||
| 2024-11-05 | Dolehide CA / Krawczyk D - Chan H / Kudermetova V | 1 - 2 | |
| Rond 1 | |||
| 2024-11-03 | Dabrowski G / Routliffe E - Chan H / Kudermetova V | 2 - 0 | |
Wuhan, Doubles
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| Rond 27 | |||
| 2024-10-11 | Chan H / Kudermetova V - Muhammad A / Pegula J | 1 - 2 | |
Statistiques de match
| 3 | Aces | 0 |
| 1 | Doubles fautes | 2 |
| 28/47 (60%) | Premier service | 40/52 (77%) |
| 20/28 (71%) | Points premier service | 23/40 (58%) |
| 9 | Service games played | 8 |
| 6/7 (85%) | Break points saved | 5/9 (55%) |
| 56 | Total | 43 |
| 32 | Point de services gagnés | 28 |
| 24 | Points gagnés au retour | 15 |
| 5 | Max de points dans une rangée | 6 |
| 12 | Total won | 5 |
| 8 | Service games won | 4 |
| 5 | Max games in a row | 2 |
| 17/40 (42%) | First serve return points | 8/28 (28%) |
| 7/12 (58%) | Second serve return points | 7/19 (36%) |
| 8 | Return games played | 9 |
| 4 | Break points converted | 1 |
| 18/19 (95%) | Deuxième service | 10/12 (83%) |
| 12/19 (63%) | Points deuxième service | 5/12 (42%) |
| 0 | Tiebreaks | 0 |
| 3 | Aces | 0 |
| 0 | Doubles fautes | 2 |
| 15/26 (58%) | Premier service | 20/26 (77%) |
| 11/11 (100%) | Deuxième service | 4/6 (67%) |
| 10/15 (67%) | Points premier service | 12/20 (60%) |
| 6/11 (55%) | Points deuxième service | 2/6 (33%) |
| 5 | Service games played | 4 |
| 4/5 (80%) | Break points saved | 3/5 (60%) |
| 16 | Point de services gagnés | 14 |
| 12 | Points gagnés au retour | 10 |
| 5 | Max de points dans une rangée | 6 |
| 8/20 (40%) | First serve return points | 5/15 (33%) |
| 4/6 (66%) | Second serve return points | 5/11 (45%) |
| 4 | Return games played | 5 |
| 2 | Break points converted | 1 |
| 3 | Max games in a row | 2 |
| 0 | Tiebreaks | 0 |
| 0 | Aces | 0 |
| 1 | Doubles fautes | 0 |
| 13/21 (62%) | Premier service | 20/26 (77%) |
| 7/8 (88%) | Deuxième service | 6/6 (100%) |
| 10/13 (77%) | Points premier service | 11/20 (55%) |
| 6/8 (75%) | Points deuxième service | 3/6 (50%) |
| 4 | Service games played | 4 |
| 2/2 (100%) | Break points saved | 2/4 (50%) |
| 16 | Point de services gagnés | 14 |
| 12 | Points gagnés au retour | 5 |
| 5 | Max de points dans une rangée | 3 |
| 9/20 (45%) | First serve return points | 3/13 (23%) |
| 3/6 (50%) | Second serve return points | 2/8 (25%) |
| 4 | Return games played | 4 |
| 2 | Break points converted | 0 |
| 0 | Tiebreaks | 0 |
| 5 | Max games in a row | 1 |
Chan H / Kudermetova V - Danilina A / Xu Y
WTA, Bad Homburg, Doubles, match Chan H / Kudermetova V - Danilina A / Xu Y, heure de début 2024-06-28 16:40:00 heure internationale.
Chan H / Kudermetova V et Danilina A / Xu Y participe au championnat Bad Homburg, Doubles, WTA.
Le match aura lieu au stade Centre Court dans la ville Bad Homburg, Allemagne.
Événements: Danilina A / Xu Y
Wimbledon, Doubles
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| Rond 6 | |||
| 2024-07-06 | Gauff C / Pegula J - Danilina A / Xu Y | 2 - 0 | |
| Rond 32 | |||
| 2024-07-04 | Frech M / Kawa K - Danilina A / Xu Y | 1 - 2 | |
Bad Homburg, Doubles
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| Rond 28 | |||
| 2024-06-28 | Chan H / Kudermetova V - Danilina A / Xu Y | 2 - 0 | |
| Rond 27 | |||
| 2024-06-27 | Danilina A / Xu Y - Nicholls O / Parry D | 2 - 0 | |
| Rond 5 | |||
| 2024-06-23 | Khromacheva I / Martins I - Danilina A / Xu Y | 0 - 2 | |
Emplacement
Allemagne
Pays
Bad Homburg
Ville
Centre Court
Stade