Tennis
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ATP
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Dubai, Doubles
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Behar A / Pavlasek A - Lammons N / Withrow J (2-1), wedstrijdresultaat, statistieken en series
Evenementen: Behar A / Pavlasek A
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Ronde 32 | |||
2024-07-04 | Machac T / Zhang Z - Behar A / Pavlasek A | 2 - 1 | |
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Ronde 5 | |||
2024-06-17 | Bublik A / Fils A - Behar A / Pavlasek A | 2 - 0 | |
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2024-06-12 | Cash J / Galloway R - Behar A / Pavlasek A | 2 - 0 | |
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Ronde 32 | |||
2024-05-31 | Behar A / Pavlasek A - Ram R / Salisbury J | 0 - 2 | |
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Ronde 5 | |||
2024-05-21 | Behar A / Pavlasek A - Mies A / Skupski N | 0 - 2 |
Match statistieken
2 | Aces | 9 |
2 | Dubbele fouten | 3 |
41/55 (75%) | Eerste opslag | 39/51 (76%) |
12/14 (86%) | Tweede opslag | 9/12 (75%) |
33/41 (80%) | Eerste opslag punten | 34/39 (87%) |
10/14 (71%) | Tweede opslag punten | 6/12 (50%) |
9 | Service games played | 9 |
2/3 (66%) | Break points saved | 0/1 (0%) |
54 | Totaal | 52 |
43 | Service punten gewonnen | 40 |
11 | Receiver punten gewonnen | 12 |
5 | Maximale punten op een rij | 5 |
9 | Total won | 9 |
8 | Service games won | 8 |
3 | Max games in a row | 3 |
5/39 (12%) | First serve return points | 8/41 (19%) |
6/12 (50%) | Second serve return points | 4/14 (28%) |
9 | Return games played | 9 |
1 | Break points converted | 1 |
0 | Tiebreaks | 0 |
0 | Aces | 4 |
1 | Dubbele fouten | 2 |
14/21 (67%) | Eerste opslag | 18/23 (78%) |
6/7 (86%) | Tweede opslag | 3/5 (60%) |
11/14 (79%) | Eerste opslag punten | 17/18 (94%) |
4/7 (57%) | Tweede opslag punten | 3/5 (60%) |
4 | Service games played | 5 |
2/3 (66%) | Break points saved | 0/0 (0%) |
15 | Service punten gewonnen | 20 |
3 | Receiver punten gewonnen | 6 |
4 | Maximale punten op een rij | 5 |
1 | Max games in a row | 3 |
1/18 (5%) | First serve return points | 3/14 (21%) |
2/5 (40%) | Second serve return points | 3/7 (42%) |
5 | Return games played | 4 |
0 | Break points converted | 1 |
0 | Tiebreaks | 0 |
2 | Aces | 3 |
0 | Dubbele fouten | 1 |
19/25 (76%) | Eerste opslag | 12/19 (63%) |
6/6 (100%) | Tweede opslag | 6/7 (86%) |
14/19 (74%) | Eerste opslag punten | 10/12 (83%) |
6/6 (100%) | Tweede opslag punten | 3/7 (43%) |
5 | Service games played | 4 |
0/0 (0%) | Break points saved | 0/1 (0%) |
20 | Service punten gewonnen | 13 |
6 | Receiver punten gewonnen | 5 |
5 | Maximale punten op een rij | 4 |
3 | Max games in a row | 1 |
2/12 (16%) | First serve return points | 5/19 (26%) |
4/7 (57%) | Second serve return points | 0/6 (0%) |
4 | Return games played | 5 |
1 | Break points converted | 0 |
0 | Tiebreaks | 0 |
0 | Aces | 2 |
1 | Dubbele fouten | 0 |
8/9 (89%) | Eerste opslag | 9/9 (100%) |
0/1 (0%) | Tweede opslag | 0/0 (0%) |
8/8 (100%) | Eerste opslag punten | 7/9 (78%) |
0/1 (0%) | Tweede opslag punten | 0/0 (0%) |
0 | Service games played | 0 |
0/0 (0%) | Break points saved | 0/0 (0%) |
8 | Service punten gewonnen | 7 |
2 | Receiver punten gewonnen | 1 |
3 | Maximale punten op een rij | 2 |
2/9 (22%) | First serve return points | 0/8 (0%) |
0/0 (0%) | Second serve return points | 1/1 (100%) |
0 | Return games played | 0 |
0 | Break points converted | 0 |
0 | Tiebreaks | 0 |
Behar A / Pavlasek A - Lammons N / Withrow J
ATP, Dubai, Doubles, match Behar A / Pavlasek A - Lammons N / Withrow J, starttijd 2024-02-27 15:45:00 internationale tijd.
Behar A / Pavlasek A en Lammons N / Withrow J neemt deel aan het kampioenschap Dubai, Doubles, ATP.
Evenementen: Lammons N / Withrow J
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Ronde 28 | |||
2024-09-05 | Purcell M / Thompson J - Lammons N / Withrow J | 2 - 0 | |
Ronde 27 | |||
2024-09-03 | Lammons N / Withrow J - Koolhof W / Mektic N | 2 - 1 | |
Ronde 5 | |||
2024-09-02 | Ram R / Salisbury J - Lammons N / Withrow J | 0 - 2 | |
Ronde 6 | |||
2024-08-31 | Eysseric J / Martin F - Lammons N / Withrow J | 1 - 2 | |
Ronde 32 | |||
2024-08-29 | Krueger M / Stalder R - Lammons N / Withrow J | 1 - 2 |