活动: Behar A / Pavlasek A
Wimbledon, Doubles | |||
回合 32 | |||
2024-07-04 | Machac T / Zhang Z - Behar A / Pavlasek A | 2 - 1 | |
Halle, Doubles | |||
回合 5 | |||
2024-06-17 | Bublik A / Fils A - Behar A / Pavlasek A | 2 - 0 | |
Stuttgart, Doubles | |||
2024-06-12 | Cash J / Galloway R - Behar A / Pavlasek A | 2 - 0 | |
Roland Garros, Doubles | |||
回合 32 | |||
2024-05-31 | Behar A / Pavlasek A - 兰姆-R/索尔兹伯里-J | 0 - 2 | |
Geneva, Doubles | |||
回合 5 | |||
2024-05-21 | Behar A / Pavlasek A - Mies A / Skupski N | 0 - 2 |
比赛统计
2 | 发球直接得分 | 9 |
2 | 双误 | 3 |
41/55 (75%) | 一发 | 39/51 (76%) |
12/14 (86%) | 二发 | 9/12 (75%) |
33/41 (80%) | 一发得分率 | 34/39 (87%) |
10/14 (71%) | 二发得分 | 6/12 (50%) |
9 | Service games played | 9 |
2/3 (66%) | Break points saved | 0/1 (0%) |
54 | 总计 | 52 |
43 | 发球得分率 | 40 |
11 | 接发球得分率 | 12 |
5 | 最多连续得分 | 5 |
9 | Total won | 9 |
8 | Service games won | 8 |
3 | Max games in a row | 3 |
5/39 (12%) | First serve return points | 8/41 (19%) |
6/12 (50%) | Second serve return points | 4/14 (28%) |
9 | Return games played | 9 |
1 | Break points converted | 1 |
0 | Tiebreaks | 0 |
0 | 发球直接得分 | 4 |
1 | 双误 | 2 |
14/21 (67%) | 一发 | 18/23 (78%) |
6/7 (86%) | 二发 | 3/5 (60%) |
11/14 (79%) | 一发得分率 | 17/18 (94%) |
4/7 (57%) | 二发得分 | 3/5 (60%) |
4 | Service games played | 5 |
2/3 (66%) | Break points saved | 0/0 (0%) |
15 | 发球得分率 | 20 |
3 | 接发球得分率 | 6 |
4 | 最多连续得分 | 5 |
1 | Max games in a row | 3 |
1/18 (5%) | First serve return points | 3/14 (21%) |
2/5 (40%) | Second serve return points | 3/7 (42%) |
5 | Return games played | 4 |
0 | Break points converted | 1 |
0 | Tiebreaks | 0 |
2 | 发球直接得分 | 3 |
0 | 双误 | 1 |
19/25 (76%) | 一发 | 12/19 (63%) |
6/6 (100%) | 二发 | 6/7 (86%) |
14/19 (74%) | 一发得分率 | 10/12 (83%) |
6/6 (100%) | 二发得分 | 3/7 (43%) |
5 | Service games played | 4 |
0/0 (0%) | Break points saved | 0/1 (0%) |
20 | 发球得分率 | 13 |
6 | 接发球得分率 | 5 |
5 | 最多连续得分 | 4 |
3 | Max games in a row | 1 |
2/12 (16%) | First serve return points | 5/19 (26%) |
4/7 (57%) | Second serve return points | 0/6 (0%) |
4 | Return games played | 5 |
1 | Break points converted | 0 |
0 | Tiebreaks | 0 |
0 | 发球直接得分 | 2 |
1 | 双误 | 0 |
8/9 (89%) | 一发 | 9/9 (100%) |
0/1 (0%) | 二发 | 0/0 (0%) |
8/8 (100%) | 一发得分率 | 7/9 (78%) |
0/1 (0%) | 二发得分 | 0/0 (0%) |
0 | Service games played | 0 |
0/0 (0%) | Break points saved | 0/0 (0%) |
8 | 发球得分率 | 7 |
2 | 接发球得分率 | 1 |
3 | 最多连续得分 | 2 |
2/9 (22%) | First serve return points | 0/8 (0%) |
0/0 (0%) | Second serve return points | 1/1 (100%) |
0 | Return games played | 0 |
0 | Break points converted | 0 |
0 | Tiebreaks | 0 |
Behar A / Pavlasek A - Lammons N / Withrow J
ATP, Dubai, Doubles, 比赛 Behar A / Pavlasek A - Lammons N / Withrow J,开始时间 2024-02-27 15:45:00 国际时间。
Behar A / Pavlasek A 和 Lammons N / Withrow J 参加冠军 Dubai, Doubles, ATP.
活动: Lammons N / Withrow J
Paris, Doubles | |||
回合 6 | |||
2024-10-28 | 奈斯,雨果 / 杰林斯基,詹 - Lammons N / Withrow J | 2 - 1 | |
Vienna, Doubles | |||
回合 27 | |||
2024-10-24 | M.冈萨雷斯 / 莫尔特尼 - Lammons N / Withrow J | 2 - 1 | |
回合 5 | |||
2024-10-21 | 吉尔-S/威力根-J - Lammons N / Withrow J | 1 - 2 | |
ATP Almaty, Kazakhstan Men Doubles | |||
回合 27 | |||
2024-10-18 | Lammons N / Withrow J - Barrientos N / Mansouri S | 1 - 2 | |
回合 5 | |||
2024-10-15 | Lammons N / Withrow J - Rodriguez C / Romios M C | 2 - 0 |