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Gomez J S / Rodriguez Rodriguez J A - Bertran P / Ogura K (2-0)，比赛结果，统计数据和系列

gomez-j-s-rodriguez-rodriguez-j-a Gomez J S / Rodriguez Rodriguez J A

bertran-p-ogura-k Bertran P / Ogura K

活动: Gomez J S / Rodriguez Rodriguez J A

Cali, Colombia Men Double Cali, Colombia Men Double
回合 29
2024-09-21 Aguilar J C / Huertas Del Pino C - Gomez J S / Rodriguez Rodriguez J A 2 - 1
回合 28
2024-09-20 Gomez J S / Rodriguez Rodriguez J A - Luz O / Rodriguez Taverna S 2 - 0
回合 27
2024-09-19 Arcila A / Heredia S - Gomez J S / Rodriguez Rodriguez J A 1 - 2
回合 5
2024-09-18 Gomez J S / Rodriguez Rodriguez J A - Duncan S / Reese H 2 - 1
Bogota, Colombia Men Double Bogota, Colombia Men Double
2024-08-07 Gomez J S / Rodriguez Rodriguez J A - Alves M / Boscardin Dias P 0 - 2

比赛统计

Gomez J S / Rodriguez Rodriguez J A

Bertran P / Ogura K
1 发球直接得分 1
3 双误 1
10 Service games played 9
5/6 (83%) Break points saved 3/6 (50%)
54 总计 49
37 发球得分率 28
17 接发球得分率 21
5 最多连续得分 7
9 Service games won 6
10/25 (40%) First serve return points 7/34 (20%)
7/20 (35%) Second serve return points 14/24 (58%)
9 Return games played 10
3 Break points converted 1
0 Tiebreaks 0
34/58 (59%) 一发 25/45 (56%)
21/24 (88%) 二发 19/20 (95%)
27/34 (79%) 一发得分率 15/25 (60%)
10/24 (42%) 二发得分 13/20 (65%)
12 Total won 7
5 Max games in a row 3
1 发球直接得分 0
2 双误 1
16/31 (52%) 一发 13/25 (52%)
13/15 (87%) 二发 11/12 (92%)
12/16 (75%) 一发得分率 7/13 (54%)
5/15 (33%) 二发得分 6/12 (50%)
5 Service games played 5
2/3 (66%) Break points saved 3/5 (60%)
17 发球得分率 13
12 接发球得分率 14
5 最多连续得分 7
6/13 (46%) First serve return points 4/16 (25%)
6/12 (50%) Second serve return points 10/15 (66%)
5 Return games played 5
2 Break points converted 1
0 Tiebreaks 0
4 Max games in a row 3
0 发球直接得分 1
1 双误 0
18/27 (67%) 一发 12/20 (60%)
8/9 (89%) 二发 8/8 (100%)
15/18 (83%) 一发得分率 8/12 (67%)
5/9 (56%) 二发得分 7/8 (88%)
5 Service games played 4
3/3 (100%) Break points saved 0/1 (0%)
20 发球得分率 15
5 接发球得分率 7
4 最多连续得分 5
4/12 (33%) First serve return points 3/18 (16%)
1/8 (12%) Second serve return points 4/9 (44%)
4 Return games played 5
1 Break points converted 0
0 Tiebreaks 0
3 Max games in a row 1

Gomez J S / Rodriguez Rodriguez J A - Bertran P / Ogura K

ITF 男子, Cancun, Doubles M-ITF-MEX-04A, 比赛 Gomez J S / Rodriguez Rodriguez J A - Bertran P / Ogura K，开始时间 2024-07-27 19:00:00 国际时间。

Gomez J S / Rodriguez Rodriguez J A 和 Bertran P / Ogura K 参加冠军 Cancun, Doubles M-ITF-MEX-04A, ITF 男子.

比赛将在体育场 Court 3 在城市中进行 HUAMANTLA, 墨西哥.

活动: Bertran P / Ogura K

Cancun, Doubles M-ITF-MEX-04A Cancun, Doubles M-ITF-MEX-04A
回合 28
2024-07-27 Gomez J S / Rodriguez Rodriguez J A - Bertran P / Ogura K 2 - 0
回合 27
2024-07-26 Mckennon M / van Emburgh J - Bertran P / Ogura K 0 - 2
回合 5
2024-07-25 Batista Mascorro I / Betancourt P - Bertran P / Ogura K 0 - 1
Santo Domingo Doubles Main Santo Domingo Doubles Main
回合 27
2023-11-16 Bertran P / Ogura K - de Boes M / Galus P 1 - 2
回合 5
2023-11-14 Bertran P / Ogura K - Jones A / Jones M 2 - 0

地点

墨西哥

国家

HUAMANTLA

市

Court 3

体育场