活动: Raghavendra K.
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回合 29 | |||
2025-01-23 | Raghavendra K. - Gelletich B. | 0 - 2 | |
回合 28 | |||
2025-01-22 | Thomas D. - Raghavendra K. | 1 - 1 | |
回合 3 | |||
2025-01-21 | Scherer S. - Raghavendra K. | 1 - 2 | |
回合 2 | |||
2025-01-20 | Okonkwo O. - Raghavendra K. | 2 - 1 | |
回合 1 | |||
2025-01-20 | Raghavendra K. - Van Assendelft J. | 2 - 0 |
可能性
Books | 1 | 2 |
---|---|---|
Bet365 |
1.83
|
1.83
|
Click on the odds to view the odds history
比赛统计
1 | 发球直接得分 | 0 |
2 | 双误 | 1 |
36/56 (64%) | 一发 | 34/54 (63%) |
18/20 (90%) | 二发 | 19/20 (95%) |
19/36 (53%) | 一发得分率 | 21/34 (62%) |
7/20 (35%) | 二发得分 | 11/20 (55%) |
10 | Service games played | 10 |
5/11 (45%) | Break points saved | 0/3 (0%) |
48 | 总计 | 62 |
26 | 发球得分率 | 32 |
22 | 接发球得分率 | 30 |
5 | 最多连续得分 | 7 |
4 | Service games won | 7 |
13/34 (38%) | First serve return points | 17/36 (47%) |
9/20 (45%) | Second serve return points | 13/20 (65%) |
10 | Return games played | 10 |
3 | Break points converted | 6 |
0 | Tiebreaks | 0 |
7 | Total won | 13 |
2 | Max games in a row | 5 |
1 | 发球直接得分 | 0 |
1 | 双误 | 0 |
15/24 (63%) | 一发 | 14/21 (67%) |
8/9 (89%) | 二发 | 7/7 (100%) |
8/15 (53%) | 一发得分率 | 9/14 (64%) |
3/9 (33%) | 二发得分 | 5/7 (71%) |
4 | Service games played | 4 |
4/7 (57%) | Break points saved | 0/1 (0%) |
11 | 发球得分率 | 14 |
7 | 接发球得分率 | 13 |
4 | 最多连续得分 | 4 |
5/14 (35%) | First serve return points | 7/15 (46%) |
2/7 (28%) | Second serve return points | 6/9 (66%) |
4 | Return games played | 4 |
1 | Break points converted | 3 |
0 | Tiebreaks | 0 |
1 | Max games in a row | 3 |
0 | 发球直接得分 | 0 |
1 | 双误 | 1 |
21/32 (66%) | 一发 | 20/33 (61%) |
10/11 (91%) | 二发 | 12/13 (92%) |
11/21 (52%) | 一发得分率 | 12/20 (60%) |
4/11 (36%) | 二发得分 | 6/13 (46%) |
6 | Service games played | 6 |
1/4 (25%) | Break points saved | 0/2 (0%) |
15 | 发球得分率 | 18 |
15 | 接发球得分率 | 17 |
5 | 最多连续得分 | 6 |
2 | Max games in a row | 2 |
8/20 (40%) | First serve return points | 10/21 (47%) |
7/13 (53%) | Second serve return points | 7/11 (63%) |
6 | Return games played | 6 |
2 | Break points converted | 3 |
0 | Tiebreaks | 0 |
系列 1
一般
Gelletich B.
胜利 3
Raghavendra K. - Gelletich B.
UTR Men, UTR Bloomington M01, 比赛 Raghavendra K. - Gelletich B.,开始时间 2025-01-23 17:40:00 国际时间。
Raghavendra K. 和 Gelletich B. 参加冠军 UTR Bloomington M01, UTR Men.
比赛将在体育场 Bloomington - Court 5 在城市中进行 Bloomington, 美国.
活动: Gelletich B.
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回合 29 | |||
2025-01-23 | Raghavendra K. - Gelletich B. | 0 - 2 | |
回合 28 | |||
2025-01-22 | Gelletich B. - Pomeranets B. | 2 - 1 | |
回合 3 | |||
2025-01-21 | Bickersteth J. - Gelletich B. | 取消 | |
2025-01-21 | Galligan D. - Gelletich B. | 0 - 2 | |
回合 2 | |||
2025-01-21 | Antonescu M. - Gelletich B. | 0 - 2 |
积分榜
2025 Bloomington M01, Group A: 2025
# | 队伍 | P | W | D | L | 进球 | 分 |
---|---|---|---|---|---|---|---|
1
|
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3 | 2 | 1 | |||
2
|
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3 | 2 | 1 | |||
3
|
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2 | 1 | 1 | |||
4
|
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3 | 1 | 2 | |||
5
|
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1 | 0 | 1 |
2025 Bloomington M01, Group B: 2025
# | 队伍 | P | W | D | L | 进球 | 分 |
---|---|---|---|---|---|---|---|
1
|
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3 | 3 | 0 | |||
2
|
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3 | 2 | 1 | |||
3
|
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3 | 1 | 2 | |||
4
|
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3 | 0 | 3 |
2025 Bloomington M01, Group C: 2025
# | 队伍 | P | W | D | L | 进球 | 分 |
---|---|---|---|---|---|---|---|
1
|
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3 | 3 | 0 | |||
2
|
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3 | 2 | 1 | |||
3
|
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2 | 1 | 1 | |||
4
|
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3 | 0 | 3 | |||
5
|
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1 | 0 | 1 |
2025 Bloomington M01, Group D: 2025
# | 队伍 | P | W | D | L | 进球 | 分 |
---|---|---|---|---|---|---|---|
1
|
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3 | 3 | 0 | |||
2
|
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3 | 2 | 1 | |||
3
|
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3 | 1 | 2 | |||
4
|
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3 | 0 | 3 |
地点
美国
国家
Bloomington
市
Bloomington - Court 5
体育场