活动: A. Chunduru
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回合 29 | |||
2025-02-16 | A. Chunduru - V. Patel | 0 - 2 | |
回合 28 | |||
2025-02-15 | Lamchinniah H. - A. Chunduru | - | |
回合 4 | |||
2025-02-12 | A. Chunduru - Irwanto J. | 0 - 2 | |
回合 3 | |||
2025-02-12 | A. Chunduru - Hsieh W. | 0 - 2 | |
回合 2 | |||
2025-02-11 | A. Chunduru - Trainauskas J. | 0 - 2 |
可能性
全场
Books | 1 | 2 |
---|---|---|
Bet365 |
5.5
|
1.13
|
Click on the odds to view the odds history
比赛统计
0 | 发球直接得分 | 7 |
3 | 双误 | 6 |
65/95 (68%) | 一发 | 52/80 (65%) |
27/30 (90%) | 二发 | 22/28 (79%) |
32/65 (49%) | 一发得分率 | 39/52 (75%) |
14/30 (47%) | 二发得分 | 14/28 (50%) |
13 | Service games played | 13 |
7/15 (46%) | Break points saved | 2/5 (40%) |
73 | 总计 | 102 |
46 | 发球得分率 | 53 |
27 | 接发球得分率 | 49 |
5 | 最多连续得分 | 8 |
5 | Service games won | 10 |
13/52 (25%) | First serve return points | 33/65 (50%) |
14/28 (50%) | Second serve return points | 16/30 (53%) |
13 | Return games played | 13 |
3 | Break points converted | 8 |
1 | Tiebreaks | 0 |
9 | Total won | 18 |
2 | Max games in a row | 6 |
0 | 发球直接得分 | 5 |
1 | 双误 | 2 |
17/28 (61%) | 一发 | 15/22 (68%) |
10/11 (91%) | 二发 | 5/7 (71%) |
7/17 (41%) | 一发得分率 | 14/15 (93%) |
8/11 (73%) | 二发得分 | 4/7 (57%) |
4 | Service games played | 4 |
15 | 发球得分率 | 18 |
4 | 接发球得分率 | 13 |
5 | 最多连续得分 | 8 |
1/15 (6%) | First serve return points | 10/17 (58%) |
4 | Return games played | 4 |
0 | Break points converted | 2 |
0 | Tiebreaks | 0 |
3/5 (60%) | Break points saved | 0/0 (0%) |
1 | Max games in a row | 3 |
3/7 (42%) | Second serve return points | 3/11 (27%) |
0 | 发球直接得分 | 2 |
2 | 双误 | 3 |
37/51 (73%) | 一发 | 29/43 (67%) |
12/14 (86%) | 二发 | 11/14 (79%) |
22/37 (59%) | 一发得分率 | 18/29 (62%) |
5/14 (36%) | 二发得分 | 5/14 (36%) |
6 | Service games played | 6 |
27 | 发球得分率 | 23 |
20 | 接发球得分率 | 24 |
5 | 最多连续得分 | 8 |
11/29 (37%) | First serve return points | 15/37 (40%) |
6 | Return games played | 6 |
3 | Break points converted | 3 |
1 | Tiebreaks | 0 |
2 | Max games in a row | 3 |
9/14 (64%) | Second serve return points | 9/14 (64%) |
3/6 (50%) | Break points saved | 2/5 (40%) |
0 | 发球直接得分 | 0 |
0 | 双误 | 1 |
11/16 (69%) | 一发 | 8/15 (53%) |
5/5 (100%) | 二发 | 6/7 (86%) |
3/11 (27%) | 一发得分率 | 7/8 (88%) |
1/5 (20%) | 二发得分 | 5/7 (71%) |
3 | Service games played | 3 |
4 | 发球得分率 | 12 |
3 | 接发球得分率 | 12 |
1 | 最多连续得分 | 7 |
1/8 (12%) | First serve return points | 8/11 (72%) |
2/7 (28%) | Second serve return points | 4/5 (80%) |
3 | Return games played | 3 |
0 | Break points converted | 3 |
0 | Tiebreaks | 0 |
0 | Max games in a row | 6 |
1/4 (25%) | Break points saved | 0/0 (0%) |
A. Chunduru - Aney A.
UTR Men, UTR Berkeley M01, 比赛 A. Chunduru - Aney A.,开始时间 2025-02-07 23:40:00 国际时间。
A. Chunduru 和 Aney A. 参加冠军 UTR Berkeley M01, UTR Men.
比赛将在体育场 Hellman Tennis Complex - Court 1 在城市中进行 Berkeley, 美国.
活动: Aney A.
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回合 29 | |||
2025-02-16 | Munk Mesa B. - Aney A. | - | |
回合 28 | |||
2025-02-15 | 阿马尔,冉 - Aney A. | 1 - 2 | |
回合 5 | |||
2025-02-14 | N. Dayal - Aney A. | 0 - 0 | |
回合 4 | |||
2025-02-12 | V. Patel - Aney A. | 0 - 2 | |
回合 3 | |||
2025-02-12 | 达斯,特伦斯 - Aney A. | 2 - 0 |
积分榜
2025 Berkeley M01, Group A: 2025
# | 队伍 | P | W | D | L | 进球 | 分 |
---|---|---|---|---|---|---|---|
1
|
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4 | 4 | 0 | |||
2
|
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4 | 3 | 1 | |||
3
|
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4 | 2 | 2 | |||
4
|
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4 | 1 | 3 | |||
5
|
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4 | 0 | 4 | |||
6
|
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0 | 0 | 0 |
2025 Berkeley M01, Group B: 2025
# | 队伍 | P | W | D | L | 进球 | 分 |
---|---|---|---|---|---|---|---|
1
|
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4 | 4 | 0 | |||
2
|
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4 | 3 | 1 | |||
3
|
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4 | 2 | 2 | |||
4
|
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4 | 1 | 3 | |||
5
|
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4 | 0 | 4 |
2025 Berkeley M01, Group C: 2025
# | 队伍 | P | W | D | L | 进球 | 分 |
---|---|---|---|---|---|---|---|
1
|
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4 | 4 | 0 | |||
2
|
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4 | 3 | 1 | |||
3
|
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4 | 2 | 2 | |||
4
|
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4 | 1 | 3 | |||
5
|
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4 | 0 | 4 |
2025 Berkeley M01, Group D: 2025
# | 队伍 | P | W | D | L | 进球 | 分 |
---|---|---|---|---|---|---|---|
1
|
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4 | 4 | 0 | |||
2
|
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4 | 3 | 1 | |||
3
|
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4 | 2 | 2 | |||
4
|
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4 | 1 | 3 | |||
5
|
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4 | 0 | 4 |
地点
美国
国家
Berkeley
市
Hellman Tennis Complex - Court 1
体育场