活动: A. Chunduru
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回合 29 | |||
2025-02-16 | A. Chunduru - V. Patel | 0 - 2 | |
回合 28 | |||
2025-02-15 | Lamchinniah H. - A. Chunduru | - | |
回合 4 | |||
2025-02-12 | A. Chunduru - Irwanto J. | 0 - 2 | |
回合 3 | |||
2025-02-12 | A. Chunduru - Hsieh W. | 0 - 2 | |
回合 2 | |||
2025-02-11 | A. Chunduru - Trainauskas J. | 0 - 2 |
可能性
Books | 1 | 2 |
---|---|---|
Bet365 |
2.75
|
1.4
|
Click on the odds to view the odds history
比赛统计
2 | 发球直接得分 | 2 |
3 | 双误 | 2 |
53/77 (69%) | 一发 | 44/73 (60%) |
21/24 (88%) | 二发 | 27/29 (93%) |
35/53 (66%) | 一发得分率 | 26/44 (59%) |
12/24 (50%) | 二发得分 | 13/29 (45%) |
81 | 总计 | 69 |
47 | 发球得分率 | 39 |
6 | 最多连续得分 | 6 |
9 | Service games won | 7 |
18/44 (40%) | First serve return points | 18/53 (33%) |
16/29 (55%) | Second serve return points | 12/24 (50%) |
5 | Break points converted | 4 |
0 | Tiebreaks | 0 |
13 | Service games played | 12 |
5/9 (55%) | Break points saved | 5/10 (50%) |
34 | 接发球得分率 | 30 |
14 | Total won | 11 |
6 | Max games in a row | 4 |
12 | Return games played | 13 |
0 | 发球直接得分 | 0 |
1 | 双误 | 1 |
18/30 (60%) | 一发 | 12/19 (63%) |
11/12 (92%) | 二发 | 6/7 (86%) |
13/18 (72%) | 一发得分率 | 5/12 (42%) |
5/12 (42%) | 二发得分 | 1/7 (14%) |
4 | Service games played | 3 |
3/4 (75%) | Break points saved | 4/7 (57%) |
18 | 发球得分率 | 6 |
13 | 接发球得分率 | 12 |
6 | 最多连续得分 | 3 |
6 | Max games in a row | 1 |
7/12 (58%) | First serve return points | 5/18 (27%) |
6/7 (85%) | Second serve return points | 7/12 (58%) |
3 | Return games played | 4 |
3 | Break points converted | 1 |
0 | Tiebreaks | 0 |
0 | 发球直接得分 | 2 |
1 | 双误 | 0 |
15/21 (71%) | 一发 | 16/23 (70%) |
5/6 (83%) | 二发 | 7/7 (100%) |
7/15 (47%) | 一发得分率 | 10/16 (63%) |
2/6 (33%) | 二发得分 | 4/7 (57%) |
4 | Service games played | 4 |
9 | 发球得分率 | 14 |
9 | 接发球得分率 | 12 |
6 | 最多连续得分 | 5 |
6/16 (37%) | First serve return points | 8/15 (53%) |
3/7 (42%) | Second serve return points | 4/6 (66%) |
4 | Return games played | 4 |
1 | Break points converted | 3 |
0 | Tiebreaks | 0 |
2/5 (40%) | Break points saved | 0/1 (0%) |
2 | Max games in a row | 4 |
2 | 发球直接得分 | 0 |
1 | 双误 | 1 |
20/26 (77%) | 一发 | 16/31 (52%) |
5/6 (83%) | 二发 | 14/15 (93%) |
15/20 (75%) | 一发得分率 | 11/16 (69%) |
5/6 (83%) | 二发得分 | 8/15 (53%) |
5 | Service games played | 5 |
20 | 发球得分率 | 19 |
12 | 接发球得分率 | 6 |
6 | 最多连续得分 | 4 |
5/16 (31%) | First serve return points | 5/20 (25%) |
5 | Return games played | 5 |
1 | Break points converted | 0 |
0 | Tiebreaks | 0 |
3 | Max games in a row | 1 |
7/15 (46%) | Second serve return points | 1/6 (16%) |
0/0 (0%) | Break points saved | 1/2 (50%) |
系列 1
一般
Ciocanu A.
失利 3
A. Chunduru - Ciocanu A.
UTR Men, UTR Berkeley M01, 比赛 A. Chunduru - Ciocanu A.,开始时间 2025-02-07 18:00:00 国际时间。
A. Chunduru 和 Ciocanu A. 参加冠军 UTR Berkeley M01, UTR Men.
比赛将在体育场 Hellman Tennis Complex - Court 3 在城市中进行 Berkeley, 美国.
活动: Ciocanu A.
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回合 28 | |||
2025-02-08 | Chunduru P. - Ciocanu A. | 2 - 0 | |
回合 5 | |||
2025-02-07 | 陈, 德里克 - Ciocanu A. | 2 - 0 | |
回合 4 | |||
2025-02-07 | A. Chunduru - Ciocanu A. | 2 - 1 | |
回合 2 | |||
2025-02-05 | 范德卡斯蒂尔,奎因 - Ciocanu A. | 2 - 0 | |
回合 1 | |||
2025-02-03 | Ciocanu A. - Aney A. | 0 - 2 |
积分榜
2025 Berkeley M01, Group A: 2025
# | 队伍 | P | W | D | L | 进球 | 分 |
---|---|---|---|---|---|---|---|
1
|
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4 | 4 | 0 | |||
2
|
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4 | 3 | 1 | |||
3
|
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4 | 2 | 2 | |||
4
|
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4 | 1 | 3 | |||
5
|
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4 | 0 | 4 | |||
6
|
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0 | 0 | 0 |
2025 Berkeley M01, Group B: 2025
# | 队伍 | P | W | D | L | 进球 | 分 |
---|---|---|---|---|---|---|---|
1
|
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4 | 4 | 0 | |||
2
|
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4 | 3 | 1 | |||
3
|
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4 | 2 | 2 | |||
4
|
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4 | 1 | 3 | |||
5
|
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4 | 0 | 4 |
2025 Berkeley M01, Group C: 2025
# | 队伍 | P | W | D | L | 进球 | 分 |
---|---|---|---|---|---|---|---|
1
|
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4 | 4 | 0 | |||
2
|
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4 | 3 | 1 | |||
3
|
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4 | 2 | 2 | |||
4
|
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4 | 1 | 3 | |||
5
|
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4 | 0 | 4 |
2025 Berkeley M01, Group D: 2025
# | 队伍 | P | W | D | L | 进球 | 分 |
---|---|---|---|---|---|---|---|
1
|
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4 | 4 | 0 | |||
2
|
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4 | 3 | 1 | |||
3
|
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4 | 2 | 2 | |||
4
|
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4 | 1 | 3 | |||
5
|
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4 | 0 | 4 |
地点
美国
国家
Berkeley
市
Hellman Tennis Complex - Court 3
体育场