网球 / ATP 挑战赛 / New Delhi, India Men Double /

Aggarwal P / Rawat S - Couacaud E / Stevenson K (0-2),比赛结果,统计数据和系列

比赛统计

0 发球直接得分 1
1 双误 2
27/42 (64%) 一发 28/46 (61%)
14/15 (93%) 二发 16/18 (89%)
15/27 (56%) 一发得分率 22/28 (79%)
5/15 (33%) 二发得分 9/18 (50%)
8 Service games played 8
35 总计 53
20 发球得分率 31
15 接发球得分率 22
5 最多连续得分 10
4 Total won 12
3 Service games won 7
2 Max games in a row 8
6/28 (21%) First serve return points 12/27 (44%)
9/18 (50%) Second serve return points 10/15 (66%)
8 Return games played 8
1 Break points converted 5
0 Tiebreaks 0
0/5 (0%) Break points saved 3/4 (75%)
0 发球直接得分 1
0 双误 1
6/13 (46%) 一发 13/24 (54%)
7/7 (100%) 二发 10/11 (91%)
2/6 (33%) 一发得分率 10/13 (77%)
3/7 (43%) 二发得分 6/11 (55%)
3 Service games played 4
5 发球得分率 16
8 接发球得分率 8
5 最多连续得分 10
1 Max games in a row 5
3/13 (23%) First serve return points 4/6 (66%)
5/11 (45%) Second serve return points 4/7 (57%)
4 Return games played 3
0 Break points converted 2
0 Tiebreaks 0
0/2 (0%) Break points saved 1/1 (100%)
0 发球直接得分 0
1 双误 1
21/29 (72%) 一发 15/22 (68%)
7/8 (88%) 二发 6/7 (86%)
13/21 (62%) 一发得分率 12/15 (80%)
2/8 (25%) 二发得分 3/7 (43%)
5 Service games played 4
0/3 (0%) Break points saved 2/3 (66%)
15 发球得分率 15
7 接发球得分率 14
4 最多连续得分 4
3/15 (20%) First serve return points 8/21 (38%)
4/7 (57%) Second serve return points 6/8 (75%)
4 Return games played 5
1 Break points converted 3
0 Tiebreaks 0
2 Max games in a row 3

Aggarwal P / Rawat S - Couacaud E / Stevenson K

ATP 挑战赛, New Delhi, India Men Double, 比赛 Aggarwal P / Rawat S - Couacaud E / Stevenson K,开始时间 2025-02-12 10:35:00 国际时间。

Aggarwal P / Rawat SCouacaud E / Stevenson K 参加冠军 New Delhi, India Men Double, ATP 挑战赛.

比赛将在体育场 Court 2 在城市中进行 New Delhi, 印度.